Question

solve the quadratic equation using formula x^2-2x-3=0​

Answer 1

Answer:

Step-by-step explanation:

here, a=1, b= -2 and c=-3

so, d= b²-4ac=4-(-12)=16.

x=(-b±√(b²-4ac))/(2a)

= - (-2)±√16

=2±4.

if x = 2+4 =6

and if x = 2-4=-2.

hence, its two zeros are 6 & -2.