Question

solve the quadratic equation with factorisation​

Answer 1

Answer:

$= \sqrt{2} {x}^{2} + 7x + 5 \sqrt{2} \\ \\ = \sqrt{2} {x}^{2} + (5 + 2)x + 5 \sqrt{2} \\ \\ = \sqrt{2} {x}^{2} + 5x + 2x + 5 \sqrt{2} \\ \\ = x( \sqrt{2} x + 5) + \sqrt{2} ( \sqrt{2} x + 5) \\ \\ = ( \sqrt{2x} + 2)((x + \sqrt{2} )$

Answer 2

Step-by-step explanation:

$\sqrt{2} {x}^{2} + 7x + 5 \sqrt{2} = 0 = > \sqrt{2} {x}^{2} + 2x + 5x + 5 \sqrt{2} = 0 = > \sqrt{2}x(x + \sqrt{2} ) + 5(x + \sqrt{2} ) = 0 = > ( \sqrt{2}x + 5)(x + \sqrt{2} ) = 0 = > x = \frac{ - 5}{ \sqrt{2} } \: or \: x = - \sqrt{2}$

hope it helps ✌