Math, asked by nagarajknaik1461, 6 months ago

Solve the quadratic equation
x^2-(2+I)x-(1-7i)=0

Answers

Answered by ngocbao9601
2

Answer:

\frac{2+i-\sqrt{7-24i} }{2} and \frac{2+i-\sqrt{7-24i} }{2}=

Step-by-step explanation:

Delta =

b^2-4ac\\(2+i)^2-4(-1+7i)\\4+4i+i^2+4-28i (i^2=-1)\\8-1-24i\\7-24i

x1=\frac{-b+\sqrt{delta} }{2a} and x2=\frac{-b-\sqrt{delta} }{2a}\\x1=\frac{2+i+\sqrt{7-24i} }{2} and x2=\frac{2+i-\sqrt{7-24i} }{2}\\

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