Solve the quadratic equation x ^2- 3(x + 3) = 0. Give
your answer correct to two significant figures.
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Answer:
Given: x2−3(x+3)=0
x2−3x−9=0
Comparing x2−3x−9 with ax2+bx+c=0, we get
a=1,b=−3,c=−9
We know, x=2a−b±b2−4ac
=2×1−(−3)±(−3)2−4×1×(−9)$
=23±9+36=23±45
=23±35=23±3×2.236
x=23±6.708
x=23+6.708 and
Step-by-step explanation:
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