Math, asked by ranjeetmatade29, 11 months ago

Solve the quadratic equation
X^2+(3x/4)^2-15^2=0

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Answers

Answered by mnandhini335
0

Answer:

x^2+9x^2/16-225

16x^2+9x^2-3600/16=0

16x^2+9x^2-3600

25x^2-3600=0

x^2-144=0

hope it's correct

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Answered by ashurao178
1

Step-by-step explanation:

x^2+(3x/4)^2-15^2=0

x^2+9x^2/16-225=0

Multiplying LHS and RHS by 16

16x^2+9x^2-3600=0

25x^2-3600=0

Reducing the numbers

x^2-144=0

x^2=144

x=root144

x=12.

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