solve the quadratic equation x^2-4-3x=0
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x^2-3x-4=0
by factorization method
x^2-4x+x-4=0
--------- -----
x(x-4)+1(x-4)=0
(x+1)(x-4)=0
x+1=0 OR x-4=0
x=-1 OR x=4
-1 OR 4 is the root of the given q.
by factorization method
x^2-4x+x-4=0
--------- -----
x(x-4)+1(x-4)=0
(x+1)(x-4)=0
x+1=0 OR x-4=0
x=-1 OR x=4
-1 OR 4 is the root of the given q.
Answered by
1
Answer
Solution set
(-1,4)
Step-by-step explanation: by factorization method
First break the mid term
X^2-3x-4
X^2-4x+x-4
X(x-4)+1(x-4)
(X+1) (x-4)
X+1=0 x-4=0
X=-1 X=4
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