Question

Solve the quadratic equation: (x^2-4x-12 =0)​

Answer 1

Answer:The solutions are x=2 ,x=−6

Step-by-step explanation:x2+4x−12=0

x2+4x=12

To write the Left Hand Side as a Perfect Square, we add 4 to both sides:

x2+4x+4=12+4

x2+2⋅x⋅2+22=16

Using the Identity (a+b)2=a2+2ab+b2, we get

(x+2)2=16

x+2=√16 or x+2=−√16

x+2=4 or x+2=−4

x=4−2 or x=−4−2

x=2 ,x=−6

Answer 2

Step-by-step explanation:

${x}^{2} - 4x - 12 = 0 \\ {x}^{2} - 6x + 2x - 12 = 0 \\ x(x - 6) + 2(x - 6) = 0 \\ (x - 6)(x + 2) = 0 \\ x - 6 = 0: x + 2 = 0 \\ x = 6 : x = - 2$

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