Math, asked by emfoster99, 8 months ago

Solve the quadratic equation x^2+6x+1=0. Give your answers to 2 decimal places.

Answers

Answered by anindyaadhikari13
12

Answer:

See this.

Step-by-step explanation:

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Answered by sadiaanam
0

Answer:

The roots of the given quadratic equation are approximately -0.17 & -5.83.

Step-by-step explanation:

To solve the quadratic equation x^2 + 6x + 1 = 0, we can use the quadratic formula, which states that the solutions for the quadratic equation ax^2 + bx + c = 0 are given by:

x = (-b ± sqrt(b^2 - 4ac)) / 2a

Comparing this formula with our given equation, we have a = 1, b = 6, and c = 1. Substituting these values in the formula, we get:

x = (-6 ± sqrt(6^2 - 4(1)(1))) / 2(1)

x = (-6 ± sqrt(32)) / 2

x = (-6 ± 5.657) / 2

Therefore, the solutions for the given quadratic equation are:

x = (-6 + 5.657) / 2 ≈ -0.17

x = (-6 - 5.657) / 2 ≈ -5.83

Hence, the roots of the given quadratic equation are approximately -0.17 and -5.83.

Learn more about quadratic equation :

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