solve the quadratic equation -x^2+x-2=0
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2
Step-by-step explanation:
multiple with - sign then use b^2-4ac rule.
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Answered by
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-x^2 -2x+x-2=0
-x(x+2)-1(x+2)
(-x-1)(x+2)
The zeroes = -2,-1
-x(x+2)-1(x+2)
(-x-1)(x+2)
The zeroes = -2,-1
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