solve the quadratic equation x : 9x-6b^2x-(a^4-b^4)=0
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5
Answer:
Step-by-step explanation:
9x² - 6b²x - (a⁴ - b⁴) =0
9x² - 3x (2b²) + (b² - a²) (b² + a²)
9x² - 3(b² - a² + b² + a²)x + (b² - a²) (b²+ a²)
9x² - 3(b² - a²)x - 3(b² + a²)x + (b² - a²) (b² + a²)
3x(3x - b² + a²) - (b² + a²) (3x - b² + a²)
(3x - b² - a²) (3x - b² + a²)
x = b² + a² /3 , b² - a²/3
x = b² + a² /3 , (b - a) (b + a) /3
At last finished. Too much time needed
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