Math, asked by vinay8566, 8 months ago

solve the quadratic equation x : 9x-6b^2x-(a^4-b^4)=0​

Answers

Answered by ankitphanzira
5

Answer:

Step-by-step explanation:

9x² - 6b²x - (a⁴ - b⁴) =0

9x² - 3x (2b²) + (b² - a²) (b² + a²)

9x² - 3(b² - a² + b² + a²)x + (b² - a²) (b²+ a²)

9x² - 3(b² - a²)x - 3(b² + a²)x + (b² - a²) (b² + a²)

3x(3x - b² + a²) - (b² + a²) (3x - b² + a²)

(3x - b² - a²) (3x - b² + a²)

x  =        b²  +  a²  /3  ,       b² - a²/3  

x  =        b²  +  a² /3   ,       (b - a) (b + a)  /3

                                         

At last finished. Too much time needed

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Answered by Anonymous
36

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