solve the quadratic equation X square minus 6x + 5 is equal to zero using formula
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Solution :
Compare x²-6x+5=0 with ax²+bx+c=0
we get ,
a = 1 , b = -6 , c = 5
Discreminant ( D ) = b² - 4ac
= ( -6 )² - 4×1×5
= 36 - 20
= 16
By quadratic formula:
x = [ (-b) ± √D ]/2a
= [ -(-6)±√16 ]/(2×1)
= ( 6 ± 4 )/2
Therefore ,
x = (6+4)/2 or x = ( 6-4 )/2
x = 5 or x = 1
•••••
Compare x²-6x+5=0 with ax²+bx+c=0
we get ,
a = 1 , b = -6 , c = 5
Discreminant ( D ) = b² - 4ac
= ( -6 )² - 4×1×5
= 36 - 20
= 16
By quadratic formula:
x = [ (-b) ± √D ]/2a
= [ -(-6)±√16 ]/(2×1)
= ( 6 ± 4 )/2
Therefore ,
x = (6+4)/2 or x = ( 6-4 )/2
x = 5 or x = 1
•••••
ghanshyam95:
thanks
this answer is wrong
It is absolutely correct.
no it is tenth level question
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