Solve the quadratic equation
(x + y) ² - 2 (x + y) = 15, xy = 6
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The value of k should -1/2 to have real and equal roots. (ii)k2x2 – 2 (2k – 1)x + 4 = 0. Solution: Given,
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Equation:- (x + y)² - 2
(x + y) = 15 [Given]
xy = 6 [Given]
(15 + 6)² - 2
[(15)² + 2(15)(6) + (6)²] - 2
[225 + 180 + 36] - 2
441 - 2
439 Ans
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