Question

solve the quadratic equation x²- 12x + 32 =0 using formula​

Answer 1

Answer:

x=(8,4)

Step-by-step explanation:

x²-12x+32=0

x²-8x-4x+32=0

x(x-8)-4(x-8)=0

(x-8)(x-4)=0

(x-8)=0 ;(x-4)=0

x=8 ; x=4

Answer 2

Answer:

$x=8, 4$

Step-by-step explanation:

Solution:-

$x=\frac{-b+/-\sqrt{b^{2}-4ac} }{2a}$

$x^{2}-12x+32=0$

Here, $a=1, b=-12, c=32$

∴ $x=\frac{-(-12)+/-\sqrt{(-12)^{2}-4(1)(32)} }{(2)(1)}$

$x=\frac{12+/-\sqrt{144-128} }{2}$

$x=\frac{12+/-\sqrt{16} }{2}$

$x=\frac{12+/-4 }{2}$

$x=\frac{12+4 }{2}, \frac{12-4 }{2}$

$x=\frac{16}{2}, \frac{8 }{2}$

∴ $x=8, 4$

∴ The values of $x$ are 8 and 4.

Verification:-

$x^{2}-12x+32=0$

If $x=8$,

$(8)^{2}-(12)(8)+32=0$

$64-96+32=0$

$64-64=0$

$0=0$

$LHS=RHS$

If $x=4$,

$(4)^{2}-(12)(4)+32=0$

$16-48+32=0$

$16-16=0$

$0=0$

$LHS=RHS$

∴ Hence verified.