Question

solve the quadratic equation x² - 3(x+3) = 0.

Answer 1

hola!

Given eqn. :
x² - 3(x+3) = 0 or x² - 3x - 9 = 0

Discriminant = b² - 4ac

= (-3)² - 4(1)(-9)

= 9 + 36

= 45 --[ roots are real n' distinct. D > 0 ]

Applying quadratic formula :-

x = -b ± √D/ 2a

x = -(-3) + √45 / 2 × 1

x = 3 ± √45/ 2

hope it helps! :)