solve the quadratic equation x²+3x=10 by factorsation method
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x²+ 3x = 10
=> x² + 3x -10 = 0
now use middle term splitting method for factorisation :-
x² + 3x - 10 = 0
=> x²+5x-2x-10 = 0
=> x(x+5) - 2(x+5) = 0
=>(x-2)(x+5)= 0
So, (x -2) = 0. or. (x+5) =0
. x = 2. or. x = -5
So the roots are 2 and -5
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