solve the quadratic equation: x²+4ix-4=0
Answers
Answered by
13
Heya !!
X² + 4X - 4 = 0
A = Coefficient of X² = 1
B = Coefficient of X = 4
And,
C = Constant term = -4
Therefore,
Discriminant ( D ) = B²-4AC
=> (4)² - 4 × 1 × -4
=> 16+16
=> 32
Therefore,
Root's of the given equations are :
-B + ✓D/2A and -B - ✓D/2A
-4 + ✓32 / 2 and -4 - ✓32/2
-4 + 4✓2 / 2 and -4 - 4✓2/2
2 ( -2 + 2✓2)/2 and -2 ( 2 + 2✓2 ) /2
-2 + 2✓2 and -2 - 2✓2 .
X² + 4X - 4 = 0
A = Coefficient of X² = 1
B = Coefficient of X = 4
And,
C = Constant term = -4
Therefore,
Discriminant ( D ) = B²-4AC
=> (4)² - 4 × 1 × -4
=> 16+16
=> 32
Therefore,
Root's of the given equations are :
-B + ✓D/2A and -B - ✓D/2A
-4 + ✓32 / 2 and -4 - ✓32/2
-4 + 4✓2 / 2 and -4 - 4✓2/2
2 ( -2 + 2✓2)/2 and -2 ( 2 + 2✓2 ) /2
-2 + 2✓2 and -2 - 2✓2 .
Answered by
2
Answer:-2i
Step-by-step explanation:
It is sq of ( x + 2i )^2 =0
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