Question

Sólve the quadratic equation x²-5/2 x - 3=0​

Answer 1

Step-by-step explanation:

Given,

x²-5/2 x - 3=0

LCM is 2

Therefore ,

$2 {x}^{2} - 5x - 6 = 0 \times 2$

$2 {x}^{2} - 5x - 6 = 0$

here,

a=2,

b={-5},

c={-6}.

The formula of roots of the quadratic equation is

$x = - b \binom{ + }{ - } \sqrt{( {b}^{2} - 4ac) } \div 2a$

$x = - ( - 5) \binom{ + }{ - } \sqrt{ {( - 5)}^{2} - 4(2)( - 6) } \div 2(2)$

x = 5+√{25+48}÷4 and x = 5-√{25+48}÷4

=} x=5+√(73)/4 and x = 5-√(73)/4