Math, asked by yashbhatt43, 3 months ago

solve the quadratic equation x2-6x+1=0​

Answers

Answered by riyabante2005
1

x²-6x+1=0

compare equation with ax²+bx+c=0

a=1,b=-6,c=1

b²-4ac=(-6)²-4×1×1

= 36-4

=32

by using Formula,

x=-b+or-/b²-4ac

2a

X=-(-6)+or-√32

2x1

x=6+or-√32

2

x=6+or-√16x2

2

x=6+or-4√2

2

x=2(3+or-2√2)

2

X=(3+or-2√2)

x=3+2√2 or x=3-2√2

x=3+2√2 or x=3-2√2 are roots of quadratic equation.

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