Question

solve the quadratic equation x2+7x-60=0 by formula method.​

Answer 1

$\sf\huge {\underline{\underline{{Solution}}}}$

x²+7x-60

By using quadratic formula

x= -b±√b²-4ac/2a

Here, a = 1 , b= 7 & c= -60

x= -7±√ 7²-4(1)(-60)/2(1)

x= -7±√ 49+240/2

x= -7±√289/2

Here,the discriminant b²-4ac is > than zero,so there will be two real roots.

x= -7±17/2

x= 10/2 or x = -24/2

x= 5 or x = -12

More to know =>

• Quadratic equation have degree 2 .
• form of a quadratic equation: is ax²+bx+c

where c is constant and not equals to zero.

• If the discriminant b²-4ac is <0 then there will be two complex roots.

Answer 2

Answer :-

x² + 7x - 60 = 0

Here a = 1 , b = 7 and c = -60

Now the formula says that x = {-b ±(√b² - 4ac)}/2

so,

x = {-7 ± (√7² - 4 × 1 × (-60)}/2

=> {-7 ± ( √49 - 240)}/2

=> { -7 ± √289}/2

=> { -7 ± 17} /2

so the roots are

{ -7 + 17} /2

=> 10/2

=> 5

and

{-7 - 17} /2

=> -24/2

=> 12

Roots are = 5 and -12

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Hope it's helpful

Thank you