Question

Solve the quadratic equation x² +x-(a+1)(a+2)=0by factoriaation method​

Answer 1

Step-by-step explanation:

x=

2a

−b±

b

2

−4ac

=

2(1)

−1±

1

2

−4{(a+2)(a+1)}

=

2

−1±

1−4{−(a

2

+3a+2)

x=

2

−1±

1+4a

2

+12a+8

=

2

−1±

4a

2

+12a+9

=

2

−1±

(2a+3)

2

=

2

−1±(2a+3)

∴x=

2

−1+2a+3

and x=

2

−1−2a−3

∴x=

2

2a+2

and x=

2

−2a−4

x=a+1x=−(a+2)