Question

solve the quadratic equation y=-x2-5x+12

Answer 1

Answer:

Use the quadratic formula to find the solutions.

−b±√b2−4(ac)2a-b±b2-4(ac)2a

Substitute the values a=1a=1, b=5b=5, and c=−12c=-12 into the quadratic formula and solve for xx.

−5±√52−4⋅(1⋅−12)2⋅1

x=−5±√732x=-5±732

The result can be shown in multipleforms.

Exact Form:

x=−5±√732x=-5±732

Decimal Form:

x=1.77200187…,−6.77200187…x=1.77200187…,-6.77200187…

x2+5x−12=0x2+5x-12=0

Step-by-step explanation:

soo min here

Answer 2

Answer:

Changes made to your input should not affect the solution:

(1): "x2" was replaced by "x^2".

Step by step solution :

STEP

1

:

Trying to factor by splitting the middle term

1.1 Factoring x2-5x-12

The first term is, x2 its coefficient is 1 .

The middle term is, -5x its coefficient is -5 .

The last term, "the constant", is -12

Step-1 : Multiply the coefficient of the first term by the constant 1 • -12 = -12

Step-2 : Find two factors of -12 whose sum equals the coefficient of the middle term, which is -5 .

-12 + 1 = -11

-6 + 2 = -4

-4 + 3 = -1

-3 + 4 = 1

-2 + 6 = 4

-1 + 12 = 11

Observation : No two such factors can be found !!