Question

Solve the quadratic equation

z^2+4iz+4=0

Answer 1

Answer:

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Step-by-step explanation:

Simplifying

z2 + 4iz + -4 = 0

Reorder the terms:

-4 + 4iz + z2 = 0

Solving

-4 + 4iz + z2 = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '4' to each side of the equation.

-4 + 4iz + 4 + z2 = 0 + 4

Reorder the terms:

-4 + 4 + 4iz + z2 = 0 + 4

Combine like terms: -4 + 4 = 0

0 + 4iz + z2 = 0 + 4

4iz + z2 = 0 + 4

Combine like terms: 0 + 4 = 4

4iz + z2 = 4

Add '-1z2' to each side of the equation.

4iz + z2 + -1z2 = 4 + -1z2

Combine like terms: z2 + -1z2 = 0

4iz + 0 = 4 + -1z2

4iz = 4 + -1z2

Divide each side by '4z'.

i = z-1 + -0.25z

Simplifying

i = z-1 + -0.25z