solve the quadratic equations : 3xsquare-2x-1=0
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3xsquare-3x+1x-1
=take 3x as common 3x(x-1)take 1as common 1(x-1)
=(3x+1)(x-1)
3x+1=0
3x=-1
x=-1/3
x-1=0
x=1
so x has two values -1/3,1
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