Question

solve the quadratic equations 9m²=25​

Answer 1

Answer:

${9m}^{2} = 25$

${9m}^{2} - 25 = 25 - 25$

${9m}^{2} - 25 = 0$

${ax}^{2} - b = ( \sqrt{ax } + \sqrt{b} )( \sqrt{ax} - \sqrt{b} ) = 0$

Then substitute the value:-

$9 {m}^{2} - 25 = ( \sqrt{9m} + \sqrt{25} )( \sqrt{9m} - \sqrt{25} ) = 0$

$(3m + 5)(3m - 5) = 0$

or,

Because the

$\sqrt{9} = + 3$

$( - 3m + 5)( - 3m - 5) = 0$

Now

we can solve the term for 0

1) 3m+5

$3m + 5= 0$

$3m + 5 - 5 = 0 - 5$

$3m + 0 = - 5$

$3m = - 5$

$\frac{3m}{3} = - \frac { 5}{3}$

$m = - \frac{5}{3}$

2)3m-5

$3m - 5 = 0$

$3m - 5 + 5 = 0 + 5$

$3m + 0 = 5$

$3m = 5$

$\frac{3m}{3} = \frac{5}{3}$

$m = \frac{5}{3}$

3) -3m+5

$- 3m + 5 = 0$

$- 3m + 5 - 5 = 0 - 5$

$- 3m + 0= - 5$

$- 3m = - 5$

$\frac{ - 3m}{ - 3} = \frac{ - 5}{ - 3}$

$m = \frac{5}{3}$

4) -3m-5

$- 3m - 5 = 0$

$- 3m - 5 + 5 = 0 + 5$

$- 3m + 0 = 5$

$- 3m = 5$

$\frac{ - 3m}{ - 3} = \frac{5}{ - 3}$

$m = \frac{5}{ - 3}$

Therefore,

$m = \frac{5}{3} \: or \: - \frac{5}{3}$

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Answer 2

Answer:

${9m}^{2} = 25$

${9m}^{2} - 25 = 25 - 25$

${9m}^{2} - 25 = 0$

${ax}^{2} - b = ( \sqrt{ax } + \sqrt{b} )( \sqrt{ax} - \sqrt{b} ) = 0$

Then substitute the value:-

$9 {m}^{2} - 25 = ( \sqrt{9m} + \sqrt{25} )( \sqrt{9m} - \sqrt{25} ) = 0$

$(3m + 5)(3m - 5) = 0$

or,

Because the

$\sqrt{9} = + 3$

$( - 3m + 5)( - 3m - 5) = 0$

Now

we can solve the term for 0

1) 3m+5

$3m + 5= 0$

$3m + 5 - 5 = 0 - 5$

$3m + 0 = - 5$

$3m = - 5$

$\frac{3m}{3} = - \frac { 5}{3}$

$m = - \frac{5}{3}$

2)3m-5

$3m - 5 = 0$

$3m - 5 + 5 = 0 + 5$

$3m + 0 = 5$

$3m = 5$

$\frac{3m}{3} = \frac{5}{3}$

$m = \frac{5}{3}$

3) -3m+5

$- 3m + 5 = 0$

$- 3m + 5 - 5 = 0 - 5$

$- 3m + 0= - 5$

$- 3m = - 5$

$\frac{ - 3m}{ - 3} = \frac{ - 5}{ - 3}$

$m = \frac{5}{3}$

4) -3m-5

$- 3m - 5 = 0$

$- 3m - 5 + 5 = 0 + 5$

$- 3m + 0 = 5$

$- 3m = 5$

$\frac{ - 3m}{ - 3} = \frac{5}{ - 3}$

$m = \frac{5}{ - 3}$

Therefore,

$m = \frac{5}{3} \: or \: - \frac{5}{3}$

HOPE IT HELPS YOU FRIEND...☺

》》Ⱥʀɳɑѵ