Question

Solve the quadratic equations-
a) 1/a+b+x=1/a+1b+1/x
(where a+b≠0)
b) 1/2a+b+x= 1/2a+1/b+1/2x
(Where 2a+b≠0)
c) (2/x+1)+3/2(x-1)=23/5x
(Where x≠1,2,0)
d) [3(7x+1/5x-3)]-[4(5x-3/7x+1)] =11 (where x≠3/5,-1/7)
e) (x-1/x+2)+(x-3/x-4)=10/3
(Where x≠2,4)
f) ax²-4ax+(a²-b²)=0
(No condition)
g) 4x²-4ax+(a²-b²)=0
(No condition)
h) (4/x)-3=[5/(2x+3)]
(Where x≠0,-3/2
-----------------------------------------
Please tell the answer as well as the explanation for each case.
Thank you. ​

Answer 1

Answer:

here is the answer of (a) part

Step-by-step explanation: