solve the quadratic polynomial p(x)=x^-x-12 and also find its zeroes
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x² - x - 12 = 0
x² - 4x + 3x - 12 = 0
x(x - 4) + 3(x - 4) = 0
x - 4 = 0 x + 3 = 0
x = 4 x = -3
So the two zeroes of the equation x²- x - 12 = 0 are 4 and -3
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