Question

Solve the quadratic quation by
factarisation method
2y2 +27 y +13=0​

Answer 1

Step-by-step explanation:

2y²+ 26y + y +13 =0

2y(y+13) + 1(y+13) =0

(2y+1) (y+13) = 0

y= -1/2 or -13

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Answer 2

Step-by-step explanation:

2y^2 + 27y + 13 =0

2y^2 + 26y + 1y + 13 =0

2y ( y + 13 ) + 1 ( y + 13 ) = 0

( y + 13 ) (2y + 1)

y + 13 = 0 , 2y + 1 = 0

y = -13 , y = - 1/2