Question

solve the quadratic
x-1/x-2 + x-3/x-4 = 10/3​

Answer 1

Answer:

$= > \frac{x - 1}{x - 2} + \frac{x - 3}{x - 4} = \frac{10}{3}$

$= > \frac{(x - 1)(x - 4) + (x - 2)(x - 3)}{(x - 2)(x - 4)} = \frac{10}{3}$

$= > \frac{ {x}^{2} - 5x + 4 + {x}^{2} - 5x + 6 }{ {x}^{2} - 6x + 8 } = \frac{10}{3}$

$= > \frac{ 2{x}^{2} - 10x + 10 }{ {x }^{2} - 6x + 8} = \frac{10}{3}$

$= > 6 {x}^{2} - 60x + 60 = 10 {x}^{2} - 60x + 80$

$= > 4 {x}^{2} + 20 = 0$

$= > {x}^{2} + 5 = 0$

$= > x = \sqrt{5}$

Hope this answer helps you ^_^ !