Math, asked by pvighnesh800, 2 months ago

Solve the quadration equation 3V5x² +25x-10V5 =0 by factorisation method.

Answers

Answered by vipashyana1
2

Answer:

3 \sqrt{5}  {x}^{2}  + 25x + 10 \sqrt{5}  = 0 \\ 3 \sqrt{5}  {x}^{2}  + 15x + 10x + 10 \sqrt{5 }  = 0 \\ (3 \sqrt{5}  {x}^{2}  + 15x) + (10x + 10 \sqrt{5} ) = 0 \\ 3 \sqrt{5} x(x +  \sqrt{5} ) + 10(x +  \sqrt{5} ) = 0 \\ (x +  \sqrt{5} )(3 \sqrt{5} x + 10) = 0

Answered by vlhoushe
1

Answer:

-2√5 or √5/3

Step-by-step explanation:

3√5x² + 25x - 10√5 = 0

3√5x² + 30x - 5x - 10√5 = 0

3x(√5x + 10) - √5(√5x + 10) =0

(√5 x+ 10) (3x - √5) = 0

√5x + 10 = 0. 3x-√5=0

X = - 10/√5. X= √5/3

X = - 10/√5 × √5/√5

X= -10√5/5

X= - 2√5

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