Question

solve the quadric equation 3x2+4√3x+4=0​

Answer 1

Answer:

x = -2/√3

Step-by-step explanation:

Given a quadratic equation such that,

$3 {x}^{2} + 4 \sqrt{3} x + 4 = 0$

To find the roots.

We will follow the middle term splitting method

Now, solving further,

Therefore, we will get,

$= > 3 {x}^{2} + 2 \sqrt{3} x + 2 \sqrt{3} x + 4 = 0$

Taking out the commom terms, we get,

$= > \sqrt{3} x( \sqrt{3} x + 2) + 2( \sqrt{3} x + 2) = 0 \\ \\ = > ( \sqrt{3} x + 2)( \sqrt{3} x + 2) = 0 \\ \\ = > {( \sqrt{3} x + 2)}^{2} = 0 \\ \\ = > \sqrt{3} x + 2 = 0 \\ \\ = > \sqrt{3} x = - 2 \\ \\ = > x = - \frac{2}{ \sqrt{3} }$

Hence, there are two equal roots and their value is -2/√3.

Answer 2

Answer:

Step-by-step explanation:

3x^2+4$\sqrt{3}$x+4=0

3x^2+2$\sqrt{3}$x+2

$\sqrt{3}$x($\sqrt{3}$x+2)+2($\sqrt{3}$x+2)

($\sqrt{3}$x+2)($\sqrt{3}$x+2)

$\sqrt{3}$x+2=0  ,  $\sqrt{3}$x+2=0

x=-2/$\sqrt{3}$  ,  x=-2/$\sqrt{3}$