Question

Solve the quation by the method of substitutio
2x+3y=9; 3x+4y=5

Answer 1

hope this helps u...........

Answer 2

2x+ 3y = 9
x = 9-3y/2

putting value of x in equation 2 we get,

3(9-3y) +4y =5
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2
taking LCM 2 and opening the brackets

27-9y +8y =5
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2

cross multiplying
27-9y+8y= 10
27-y = 10
27-10= y
17 =y

putting value of y in equation 1
2x+ 3(17) = 9
2x + 51 = 9
2x = 9-51
2x= -42
x= -21

here is the answer mate.
hope it helps you.
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