Question

solve the qudratic equation.plxx​

Answer 1

==> 13x² - 66x + 81 = 0

==> 13x² - 39x - 27x + 81 = 0

==> 13x ( x - 3 ) - 27 (x - 3 ) = 0

==> ( x - 3 ) ( 13x - 27 )

Zeroes of the quadratic equation are 3 and 27/13

Answer 2

Step-by-step explanation:

x= -b + - √b²- 4ac whole divided by 2a

x= -(-66)+-√(66)²- 4×13×81 / 2×13

x= 66+-√4356 - 4212 / 26

x= 66+-√ 144 / 26

x= 66+12/26 & 66 - 12/26

x= 3 & x= 27/13