Question

solve the qudratic equation see the picture of question icse students can only can solve this equation answer is=
5,18 specially for ICSE students.​

Answer 1

AnsWer :

x = 18 and x = 5.

Concepts Required :

• General equation of quadratic Equation,i.e. ax² + bx + c=0.
• Where, a not equal to 0.

Solution :

We have equation,

$\tt \implies \frac{x}{5} + \frac{28}{x + 2} = 5.$

$\tt \implies \frac{x(x + 2) + 140}{5(x + 2)} = 5.$

$\tt \implies \frac{ {x}^{2} + 2x + 140}{5(x + 2)} = 5.$

$\tt \implies {x}^{2} + 2x + 140= 5(5x + 10).$

$\tt \implies {x}^{2} - 23x + 90 = 0.$

Compare with General Equation,

ax² + bx + c = 0.

Where,

• a = 1.
• b = -23.
• c = 90.

Splitting the middle term,

$\tt \implies {x}^{2} - 18x - 5x + 90 = 0.$

$\tt \implies x(x - 18) - 5(x - 18 )= 0.$

$\tt \implies (x - 5)(x - 18) = 0.$

Either,

$\tt \implies x - 5 = 0.$

$\tt \implies x = 5.$

And,

$\tt \implies x - 18 = 0.$

$\tt \implies x = 18.$

Therefore, the value of required Answer is 5 and 18.

Answer 2

Answer:

x = 5 , 18

For solution , please refer to the attachment.