Question

solve the ques in attachment

step by step explanation needed!!

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Answer 1

Answer:

Net Force will be 30 N.

Explanation:

According to the Question

It is given that there are three forces acting on a box . Different in magnitude .

• Force acting in downward direction ,FD = 10N
• Force acting in Upward direction ,FU = 10N
• Force acting on the left side of box ,FL = 30N

we need to calculate the net force acting on the box .

As we know that net force is calculated by the sum of there magnitude .

• Net Force = Sum of All Forces

Substitute the value we get

➻ Net Force = FD + FU + FL

➻ Net Force = 10N + (-10N) + 30N

➻ Net Force = 10N - 10N + 30N

➻Net Force = 0N + 30N

➻Net Force = 30N

we take here FU as negative because it is acting in the opposite side of FD .

• Hence, the Net Force acting on the box will be 30 N.

Answer 2

GIVEN :-

According to the figure given of force,

We are given with 3 sides,

• Force applied from left side of box, FL = 30N
• Force applied from upward direction of box, FU = 10N
• Force applied from downward direction of box, FD = 10N

TO FIND :-

Net force acting on the box.

SOLUTION :-

We know that net force is equal to the sum of its magnitude.

$\sf \fbox \orange{Net \: Force = Sum \: of \: All \: Force}$

Substituting the values in the formula,

⇒ Net Force = FL + FU + FD

⇒ Net Force = 30N + 10N + (-10N)

⇒ Net Force = 30N + 10N -10N

⇒ Net Force = 30N + 0N

⇒ Net Force = 30N

[NOTE : FD is taken negative because it is acting opposite to upward force.]

∴The net force acting on the box is 30N.