Question

Solve the ques in the attachment please

Answer 1

Here your answer goes

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First Method !

Step :-1

Let the length be l

So , Breadth = l - 3

Area = l( l - 3 )

Step :- 2

The area of isosceles triangle

⇒ $\frac{1}{2} * (l -3) * 12$

⇒ $6(l-3)$

Step :- 3

According to the question ,

⇒ $l(l-3)-4=6(l-3)$

⇒ $l^2 - 3l-4 = 6l-18$

⇒ $l^2 - 9l +14 =0$

⇒ $l^2 - 2l - 7l + 14l = 0$

⇒ $l(l-7)-2(l-7)$

⇒ $( l-2) ( l-7) = 0$

length = 7 m

Breadth = (l -3 ) ==>> ( 7 - 3 ) = 4 m

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Second Method !

Refer to this attachments  with my answer

↓↓

Be Brainly

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Answer 2

Let the length of the rectangular park be x.

Then, the breadth of the rectangular park = x - 3

(i)

⇒ Area of the rectangular park = length * breadth

                                                    = x(x - 3) m.

(ii)

From the figure,

Base of an isosceles triangle = x - 3 m..

Height = 12 m.

⇒ We know that Area of an isosceles triangle = (1/2) * base * height

                                                                             = (1/2) * (x - 3) * 12

                                                                             = 6x - 18.

(iii)

Given that area of rectangular park is 4 m^2 more than area of triangular park.

⇒ x(x - 3) = 6x - 18 + 4

⇒ x^2 - 3x = 6x - 14

⇒ x^2 - 9x + 14 = 0

⇒ x^2 - 2x - 7x + 14 = 0

⇒ x(x - 2) - 7(x - 2) = 0

⇒ (x - 2)(x - 7) = 0

⇒ x =2,7

When x = 2:

Breadth = (x - 3)

             = (2 - 3)

             = -1.{It cannot be negative}

When x = 7:

Breadth = x(x - 3)

             = (7 - 3)

             = 4.

Therefore,

⇒ Length of the rectangular park = 7 m.

⇒ Breadth of the rectangular park = 4 m.

Hope it helps!