Math, asked by ishubhattvs6, 11 months ago

solve the ques in the figure.
plx tell how to find y axis in the graph ...like in this image ..
i will mark you as BRAINLIEST ​

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Answers

Answered by stk9849
0

Answer:

3x-2y+4=0 >equ 1

2x+2y+6 =0 > equ2

x-0+10=0

i.e,x=10

now substitute x=10 in equ 1

and then

3(10)-2y+4=0

34= 2y

y= 17

now plot these on the graph the you can find the rest of the answer to question

Answered by MajorLazer017
4

Answer:

here it is mate

Step-by-step explanation:

CORRECTION IN THE QUESTION:: EQ 2 IS x - y + 3 = 0

now,

eq 1 === 3x - 2y +4 =0

put x = 0 then,y=2 (0,2)

put,x=2 then y = 5 (2,5)

put, x=4 then, y =8 (4,8)

now,

eq 2 === x-y + 3 = 0

put x =0 then y = 3(0,3)

put y=0 then x = -3 (-3,0)

put x =1 then y =4(1,4)

now..

look at the image attached...

2,5 is the point of intersection

PLEASE MARK AS THE BRAINLIEST..

YOUR SUPPORT IS VERY MUCH VALUABLE TO ME...

AS FOR THE AREA...

HEIGHT = 4CM

BREADTH = 2CM

THEN AREA, ½BH = ½ × 4 × 2 = 4cm²

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