solve the ques in the figure.
plx tell how to find y axis in the graph ...like in this image ..
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Answered by
0
Answer:
3x-2y+4=0 >equ 1
2x+2y+6 =0 > equ2
x-0+10=0
i.e,x=10
now substitute x=10 in equ 1
and then
3(10)-2y+4=0
34= 2y
y= 17
now plot these on the graph the you can find the rest of the answer to question
Answered by
4
Answer:
here it is mate
Step-by-step explanation:
CORRECTION IN THE QUESTION:: EQ 2 IS x - y + 3 = 0
now,
eq 1 === 3x - 2y +4 =0
put x = 0 then,y=2 (0,2)
put,x=2 then y = 5 (2,5)
put, x=4 then, y =8 (4,8)
now,
eq 2 === x-y + 3 = 0
put x =0 then y = 3(0,3)
put y=0 then x = -3 (-3,0)
put x =1 then y =4(1,4)
now..
look at the image attached...
2,5 is the point of intersection
PLEASE MARK AS THE BRAINLIEST..
YOUR SUPPORT IS VERY MUCH VALUABLE TO ME...
AS FOR THE AREA...
HEIGHT = 4CM
BREADTH = 2CM
THEN AREA, ½BH = ½ × 4 × 2 = 4cm²
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