Question

Solve the questio 4,5 and 6 in exercise 6.3

Answer 1

Answer:

2x+ 50°=180°(angle sum property)

2x=180°- 50°=130°

2x=130°

x=130°/2

x=75°

5th question

2x+x+90°=180°

3x+90°=180°

3x=180°-90°

3x=90°

x=90°/3

x=30°

Answer 2

★ How to do :-

Here, we are given with three diagrams consisting a triangle with some variables as x. We are asked to find the value of those variables. So, here we are going to use the concept of triangle's interior angles property, in which it days that all the angles in the interior of the triangle always add up together as 180°. So, we can apply this rule and solve the question. So, let's solve!!

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➤ Solution (1) :-

Here, we are given with one angle as 50° and other two angles are named as x.

Value of 'x' :-

${\tt \leadsto 50 + x + x = 180}$

Add the both the variables x.

${\tt \leadsto 50 + 2x = 180}$

Shift the number 50 from LHS to RHS and change it's sign.

${\tt \leadsto 2x = 180 - 50}$

Subtract the values.

${\tt \leadsto 2x = 130}$

Shift the number 2 from LHS to RHS and change it's sign.

${\tt \leadsto x = \dfrac{130}{2}}$

Simplify to get the value of 'x'.

${\tt \leadsto \orange{\underline{\boxed{\tt x = {65}^{\circ}}}}}$

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➤ Solution (2) :-

${\tt \leadsto x + x + x = 180}$

Add all the variables of x and write as 3x.

${\tt \leadsto 3x = 180}$

Shift 3 from LHS to RHS and change it's sign.

${\tt \leadsto x = \dfrac{180}{3}}$

Simplify to get the value of 'x'.

${\tt \leadsto \orange{\underline{\boxed{\tt x = {60}^{\circ}}}}}$

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➤ Solution (3) :-

${\tt \leadsto x + 2x + 90 = 180}$

Add both the variables.

${\tt \leadsto 3x + 90 = 180}$

Shift 90 from LHS to RHS and change it's sign.

${\tt \leadsto 3x = 180 - 90}$

${\tt \leadsto 3x = 90}$

Shift 3 from LHS to RHS and change it's sign.

${\tt \leadsto x = \dfrac{90}{3}}$

Simplify to get the value of'x'.

${\tt \leadsto \orange{\underline{\boxed{\tt x = {30}^{\circ}}}}}$

Hence solved !!