Solve the question(1-2i)-²
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(1-2i)²
= (1)²-2×1×2i+(2i)²
= 1-4i+4i²
= 1-4i+4(-1)
= 1-4i-4
= -3-4i
Answered by
1
Answer:
Step-by-step explanation:
(1 - 2i) -² = 1/(1 - 2i)²
= 1/1² - 4i + 4i²
i² = i × i = √-1 × √-1 = -1
1/(1² - 4i + 4i²) = 1/(1 - 4i -4) =>
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