Question

solve the question ​

Answer 1

s = ut +1/2 g t^2

30 = u + 9.8/2

u =30- 4.9 = 25.1

V^2 = u^2 + 2gs

now from top initial velocity u of upper point becomes final velocity

(25.1)^2 = 2(9.8)s

630.01/19.6 = s

32.14 = s

So 32.14 m above upper point it began to fall