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Answer:
0.46
Step-by-step explanation:
radius of conical vessel = 8cm
height of conical vessel = 15 cm
therefore volume = 1/3 πr²h = 1/3 π 8² 15 = 320πcm³
let radius of the sphere be r cm
in right Δosp by pythogoras theorem
l²= 8²+15²
⇒ l = sqrt of 64+225= 17 cm = 8/17 .....1
hence sin Ф = pm/tp = r/ tp⇒ 8/17 ⇒ r /15-r 120 - 8r = 17r ⇒120 = 25r
r = 120/25 ⇒4.8r
vol of sphere = 4/3 πr³ = 4/3 π (4.8³)cm³ = 147.45πcm³
vol of water = vol of cone = 320 π cm³
vol of water flows out = vol of sphere = 147.45π/320π = 0.46
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Meh.................
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