Question

solve the question ​

Answer 1

Answer:

a) 0-10 seconds on v/t graph shows positive acceleration.

v=20m/s, t=10s.

a=20m/10s^2

=2 m/s²

b)Line BC shows retardation.

v= -20m/s, t=10s

a=-2m/s²

c)displacement = velocity×time

s of OA=1/2×20×10=100m

s of AB=20×20=400m

s of BC=1/2×-20×10=-100m

s = OA+AB+BC=100+400-100=400m

s=400m

Answer 2

5)a) OA shows acceleration.

      Acceleration=Change of velocity /Time

  ⇒Acceleration=20-0/10m/s²

  ⇒Acceleration=2m/s²

  b) BC shows retardation.

      Retardation=Change of velocity /Time

   ⇒Retardation=-(40-30)/10m/s²

   ⇒Retardation=-2m/s²

  c) Total distance covered=Area of the Trapezium

   ⇒Total distance covered=(AB+OC)h/2

   ⇒Total distance covered=(20+40)20/2

   ⇒Total distance covered=60×10

   ⇒Total distance covered=600m