Question

solve the question
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Answer 1

Answer:

Let C be the point at which the tree is broken and let the top of the tree touch the ground at A.

Let B denote the foot of the tree.

Given AB=30m and ∠CAB=30

∘

In the right angled △CAB,

$⇒BC=ABtan30∘</p><p></p><p>∴BC=330</p><p></p><p>=103m               (1)</p><p></p><p>Now,  cos30∘=ACAB</p><p></p><p>⇒AC=cos30∘AB</p><p></p><p>So, </p><p></p><p>AC=330×2=103×2=203m.                                          (2)</p><p></p><p>Thus, the height of the tree =BC+AC=103+203</p><p></p><p> =303m.</p><p></p><p>$

Miss.Heartless

➜■Alena■

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Answer 2

$\mathfrak{\huge\underline{Question:}}$ ,

A tree is broken over by the wind and the broken part of the tree touches the ground making an angle of 30° with it. The distance between the foot of the tree and the point where the top of the tree touches the ground is 6 m. Find the height of the tree before it was broken.

$\mathfrak{\huge\underline{Answer:}}$ ,

in above attachment⤴️