Question

solve the question.​

Answer 1

$\huge\tt{\bold{\underline{\underline{Question᎓}}}}$

To Rationalise:

$\huge\bold{ \frac{4}{ \sqrt{3} + \sqrt{2} }}$

$\huge\tt{\bold{\underline{\underline{Answer᎓}}}}$

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$\bold{= > \frac{4}{ \sqrt{3} + \sqrt{2} } }$

=>To Rationalise we multiply both numerator and denominator with opposite sign of denominator.

=>If denominator is positive value then multiply with negative sign to both numerator and denominator and vice versa

$\bold{= > \frac{4}{ \sqrt{3} + \sqrt{2} } \times \frac{ \sqrt{3} - \sqrt{2} }{ \sqrt{3} - \sqrt{2} }}$

$\bold{= > \frac{4( \sqrt{3} - \sqrt{2} )}{ {( \sqrt{3} )}^{2} - {( \sqrt{2}) }^{2} }}$

$\mathcal{Here,this\: identity \:is \:used:-}$

$\bold{\boxed{ = > {x}^{2} - {y}^{2} = (x + y)(x - y)}}$

$= > \frac{4( \sqrt{3} - \sqrt{2} ) }{3 - 2}$

$\bold{\red{= > 4( \sqrt{3} - \sqrt{2} )}}$

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