Question

Solve the question 2t^2-t-10

Answer 1

$2 {t}^{2} - t - 10 = 0 \\ \\ 2 {t}^{2} - 5t + 4t - 10 = 0 \\ \\ t(2t - 5) + 2(2t - 5) = 0 \\ \\ (t + 2)(2t - 5) = 0 \\ \\ t = - 2...........t = \frac{5}{2}$

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Answer 2

Answer:

Step-by-step explanation: