Question

solve the question 3aupon 10 + 2a upon 5 is equals to 7a upon 25 + 29 upon 25

Answer 1

$\frac{3a}{10} + \frac{2a}{5} = \frac{7a}{25} + \frac{29}{25}$
$\frac{3a + 4a}{10} = \frac{7a + 29}{25}$
$\frac{7a}{2} = \frac{7a + 29}{5}$
$35a = 14a + 58$
$35a - 14a = 58$
$21a = 58$
$a = \frac{58}{21}$

Answer 2

Answer:

$\frac{3a}{10}  +  \frac{2a}{5}  =  \frac{7a}{25} +  \frac{29}{25}$

$\frac{3a + 4a}{10}  =  \frac{7a + 29}{25}$

$\frac{7a}{2}  =  \frac{7a + 29}{5}$

$35a = 14a + 58$

$35a - 14a = 58$

$21a = 58$

$a =  \frac{58}{21}$

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