Question

Solve the question

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Answer 1

Answer:

znxnndndnxnxndnnxnxncnnxnxncnfncnncnx

Explanation:

speed by time into distance I guess

Answer 2

Answer:

The motion of the boy can be considered in three parts.

In the first part,he walks a distance :

D = 0.5 km in time in T = 10 minutes

$\bf Speed \: v \: = \frac{D}{T} = \frac{0.5 \: km}{10 \: min} \\ \bf \red {= 0.05 \: km \: {min}^{ - 1} }$

In the second part,he walks a distance :

D = 1.0 km in time in T = 20 minutes

$\therefore \bf Speed \: v \: = \frac{D}{T} = \frac{1.0 \: km}{20 \: min} \\ \bf \pink {= 0.05 \: km \: {min}^{ - 1} }$

In the third part,he walks a distance:

D = 1.5 km in T = 30 minutes

$\therefore \bf Speed \: v \: = \frac{D}{T} = \frac{1.5 \: km}{30 \: min} \\ \bf \blue {= 0.05 \: km \: {min}^{ - 1} }$

Thus,the speed of body remains same throughout his journey. Hence,his motion is uniform.

Now 1 km = 1000 m and 1 minute = 60s.

$\bf Average \: speed \: of \: the \: boy \\ \bf = 0.05 \: km \: {min}^{ - 1}$

$\bf \purple {= \frac{0.05 \times 1000 \: m}{60 \: s} = \frac{50 \: m}{60 \: s} = 0.83 \: m \: {s}^{ - 1} }$