Question

solve the question 5 pe power 3/2 /5 pe power 1/2​

Answer 1

Answer:

F1(t) is the cubic function;

F2(t) is the exponential function;

F3(t) is the quadratic function.

Here are some observations which lead to these conclusions.

All power functions ktp with p 0 are zero for t = 0. Thus F2 cannot be a power function.

Assuming that F1(t) = ktn with n = 2 or n = 3, we can evaluate F1(1) to obtain k. In this case, k = 2.5.

Since F1(t) = (2.5)tn with n = 2 or n = 3, we can figure out n by evaluating at t = 1.2.

(2.5)(1.2)2 = 3.6 and (2.5)(1.2)3 = 4.32,

so n = 3

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