Physics, asked by BananaPants, 1 year ago

solve the question 50 points. !!

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Answered by Anonymous
9
Moment of inertia due to remaining disc= Moment of inertia due to disc - moment of inertia due to disc having radius R/3

Due To disc I= 1/2 MR^2

Due to disc having Radius R/3

Mass of R/3 radius disc= M/pie r^2 × pie (R/3)^2

= M/9

I= 1/2 M ( R/3)^2 /9+ M ( R-R/3)^2 /9( parallel axis theorem)

=1/9( 1/2 M × R^2/9 + M ( 2R/3)^2)

= 1/9(MR^2/18 + M× 4R^2/9)

= 1/9(MR^2 + 8MR^2)/18)

= 1/9(MR^2/2)

= MR^2/18

So I= MR^2/2 - MR^2/18

= 9MR^2 - MR^2)/18

= 8MR^2/18

= 4MR^2/9

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Answered by xxAjayxx
0

Answer:

Self-image is O Images of the self in our minds O Image of self in others minds O Imagination O Magical transformation O

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