solve the question
√(7+3√5)=?
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√(7+3√5)=√[(14+6√5)/2]
=√[{9+2×3×√5+5}/2]
=√[{(3)^2+2×3×√5+(√5)^2}/2]
=√[{3+√5}^2/2]
=+-(3+√5)/√2
=√[{9+2×3×√5+5}/2]
=√[{(3)^2+2×3×√5+(√5)^2}/2]
=√[{3+√5}^2/2]
=+-(3+√5)/√2
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