Question

solve the question .........

Answer 1

Answer:

given , x=3

quadratic equation ==> x²-2kx-6 = 0

so, putting value of x in quadratic  equation

==> (3)²-2k(3)-6 = 0

==> 9-6k-6 = 0

==> 3(3-2k-2) = 0

==> 3-2-2k = 0/3

==> 1-2k = 0

==> -2k = -1

==> k = -1/-2

==> k = 1/2